0=96-16x^2

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Solution for 0=96-16x^2 equation:



0=96-16x^2
We move all terms to the left:
0-(96-16x^2)=0
We add all the numbers together, and all the variables
-(96-16x^2)=0
We get rid of parentheses
16x^2-96=0
a = 16; b = 0; c = -96;
Δ = b2-4ac
Δ = 02-4·16·(-96)
Δ = 6144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{6144}=\sqrt{1024*6}=\sqrt{1024}*\sqrt{6}=32\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32\sqrt{6}}{2*16}=\frac{0-32\sqrt{6}}{32} =-\frac{32\sqrt{6}}{32} =-\sqrt{6} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32\sqrt{6}}{2*16}=\frac{0+32\sqrt{6}}{32} =\frac{32\sqrt{6}}{32} =\sqrt{6} $

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